Question

Sum of the ages of two brothers is 36 years. If the difference
between their ages is 10. Find their ages​

Answer 1

Answer:

The sum of the ages of A and B is 36 years

The sum of the ages of A and B is 36 yearsLet the ages of A be x and B be y

The sum of the ages of A and B is 36 yearsLet the ages of A be x and B be yx + y = 36

The sum of the ages of A and B is 36 yearsLet the ages of A be x and B be yx + y = 36x = 36 - y (Equation 1)

The difference between their ages is 10.

x - y = 10

x = 10 + y (Equation 2)

Substituting the value of x from Eq.1 to Eq.2

Substituting the value of x from Eq.1 to Eq.236 - y = 10 + y

+ y-y - y = 10 - 36

- 36-2y = -26

y = 26/2

/2y = 13

Substituting the derived value of y in Eq..1

Substituting the derived value of y in Eq..1x = 36 - y

Substituting the derived value of y in Eq..1x = 36 - yx = 36 - 13

x = 23

The age of A is 23 years and the age of B is 13 years.

Answer 2

Answer:

x=23 y=13

Step-by-step explanation:

let x and y be the age of two brothers

A/q

x+y=36----------1

x-y=10-------------2

On adding 1st and 2nd,we get

2x=46

x=23

y=36-23

y=13