Question

sum of the agesof father and his son is 60 years.after 14 years,father's age will be three times the age of the son.find their present age​

Answer 1

Answer:

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Step-by-step explanation:

Let father's age be x

Son age = 60-x

Sum of their ages= 60

After 14 years,

Father's age= x+14

Son age= 60-x+14 =74-x

Given,

Father's age= 3(age of his son)

= x+14 = 3(74-x)

= x+14 = 222 - 3x

= 4x = 288

= x = 52

Father's age = x = 52

Son age = 60 - 52 = 8

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Answer 2

S O L U T I O N :

Let the present age of son's be r years & let the present age of father's be m years respectively.

A/q

$\mapsto\tt{r+m=60}$

$\mapsto\tt{r=60-m..................(1)}$

&

$\underbrace{\bf{14\:years\:later\::}}$

The age of son's will be = (r+14) years .

The age of father's will be = (m+14) years .

$\mapsto\tt{(m+14) = 3(r+14)}$

$\mapsto\tt{m+14 = 3r + 42}$

$\mapsto\tt{m + 14 = 3(60-m) + 42\:\:\:[from(1)]}$

$\mapsto\tt{m+14 = 180 -3m + 42}$

$\mapsto\tt{m+14 = -3m +222}$

$\mapsto\tt{m+3m = 222-14}$

$\mapsto\tt{4m = 208}$

$\mapsto\tt{m = \cancel{208/4}}$

$\mapsto\bf{m=52\:years}$

∴ Putting the value of m in equation (1),we get;

$\mapsto\tt{r=60-52}$

$\mapsto\bf{r=8\:years}$

Thus;

The present age of the son's = r = 8 years .

The present age of the father's = m = 52 years .