Math, asked by mlal47057, 11 months ago

sum of the agesof father and his son is 60 years.after 14 years,father's age will be three times the age of the son.find their present age​

Answers

Answered by mbakshi37
11

Answer:

S + F = 60

F+14 = 3x (S +14)

60-S +14 =3S + 42

4S = 32

S= 8

F=52

Sir , Now please Brainliest.

Answered by amansharma264
28

EXPLANATION.

Let the age of father be = x years.

Let the age of his son be = y years.

sum of ages of father and his son = 60

=> x + y = 60 ......(1)

after 14 years,

present age of father = ( x + 14 ) years.

present age of his son = ( y + 14 ) years.

father age will be three times the age

of the son.

=> 3 ( y + 14 ) = ( x + 14 )

=> 3y + 42 = x + 14

=> x - 3y = 28 .....(2)

From equation (1) and (2) we get,

=> x + y = 60 ..... (1)

=> x - 3y = 28 .....(2)

multiply equation (1) by 3

multiply equation (2) by 1

we get,

=> 3x + 3y = 180

=> x - 3y = 28

=> 4x = 208

=> x = 52

put the value of x = 52 in equation (1)

we get,

=> 52 + y = 60

=> y = 8

Therefore,

age of father = x = 52 years.

age of his son = y = 8 years.

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