Question

sum of the angle measures of any

triangle is 180°. Find the angle measures of
a triangle if the second angle measures 10
less than twice the first, and the third angle
measures 25 more than the second.


​

Answer 1

$\bf{\red{\underline{\bf{Given}}}}$

• The sum of the angle measures of any triangle is 180°. Find the angle measures of a triangle if the second angle measures 10° less than twice the first, and the third angle measures 25° more than the second.

$\bf{\red{\underline{\bf{To\;Find}}}}$

• Angles of triangle

$\bf{\red{\underline{\bf{Solution}}}}$

• ➠ Let the first angle be x °

Then,

• ➠ Second angle = ( 2x - 10)°

• ➠ Third angle = (2x - 10) + 25 = (2x + 15)

Now,

We know that,

• ➤ Sum of angles of triangle = 180°

So,

• ➭ x + (2x - 10) + (2x + 15) = 180

• ➭ 5x + 5 = 180

• ➭ 5x = 180 - 5

• ➭ x = 175/5

• ➭ x = 35

Therefore,

➦ First angle = x = 35°

➦ Second angle = (2x - 10) = 2×35 - 10 = 70-10 = 60°

➦ Third angle = (2x + 15) = 2×35 + 15 = 70 + 15 = 85°

Answer 2

Answer:

let the 1st no. be x

2nd no. be 2x-10

3rd no. be 2x-10+25

A.T.Q

x+2x-10+2x-10+25=180

5x+5=180x=37

put the value of x in those ....