sum of the area of two sqares is 640 sqm. If the difference between the perimeter of the sqares is 64m find the length of the sqares
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Answered by
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hi!!!!!!!!
Sum of the area of two squares is 640
=> x+y=640 sq. m. -------(1)
Difference between the perimeter of the squares is 64
=> x-y=64 cm. --------(2)
from (1)&(2)
x+x+y-y=640+64
2x =704
x =704/2
x =352
substitute x values in both equation(1)
x+y=640
352+y=640
y=640-352
y=288
x=352 and y=288
Hope it hlpzzz......
FOLLOW ME!!!!!!
Sum of the area of two squares is 640
=> x+y=640 sq. m. -------(1)
Difference between the perimeter of the squares is 64
=> x-y=64 cm. --------(2)
from (1)&(2)
x+x+y-y=640+64
2x =704
x =704/2
x =352
substitute x values in both equation(1)
x+y=640
352+y=640
y=640-352
y=288
x=352 and y=288
Hope it hlpzzz......
FOLLOW ME!!!!!!
Answered by
1
Now ,
putting the value b=8 in equation(I)
a = 16+8
a = 24 m.
Hope it's helpful.............
If it's a helpful answer then plz mark it brilliant answer........
putting the value b=8 in equation(I)
a = 16+8
a = 24 m.
Hope it's helpful.............
If it's a helpful answer then plz mark it brilliant answer........
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