Sum of the area of two square is 544m square.if the difference of their perimeter s is 32 , find the side of the square
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Answer:
Area of square =a^
perimeter of square=4a
Let 1st square side be x and 2nd square side be y
4x-4y=32
4(x-y)=32
x-y=8
x=8+y............,............{1}
ATQ
x^+y^=544
from{1}
(8+y)^+y^=544
64+16y+y^+y^=544
2y^+16y=490
2y^+16y-490=0>>>>>>>>divide it by 2
y^+8y-245=0
By formula method
-b+-✓b^-4ac/2a
-8+✓64+980/2
-8+-30.2
38.2 or -38.2
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