Question

Sum of the areas of the two squares is 400 cm if the difference of their perimeter is 16 cm find the sides of the two squares.

Answer 1

That's a classical question !

Let side of squares be x and y cm respectively.
Then,
x² + y² = 400 ----- (i)

And,
4y - 4x = 16
y = 4+x

Put this value in (i),

> x² + (4+x)² = 400
> x² + 16 + x² + 8x = 400
> 2x² + 8x = 384
> x² + 4x = 192

Solve the equation and you will get x, and then put that in (i), you will get the sides !

Hope it helps !

(Please comment if you have any problem solving the equation)

Answer 2

hope it helps!;!;!;!