sum of the areas of two sauare are 468cm ² . If the difference of their perimeter is 24 m . Find the side of two squares.
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let the area of 1st sq. be x*x
"" "" " " 2. "" " y*y
A. T. Q
x²+y²=468. .......(1)
& x-y =24
x=24+y
(24+y)²+y²=468
576+y²+48y+y²=468
2y²+48y+576-468=0
2y²+48y+92
"" "" " " 2. "" " y*y
A. T. Q
x²+y²=468. .......(1)
& x-y =24
x=24+y
(24+y)²+y²=468
576+y²+48y+y²=468
2y²+48y+576-468=0
2y²+48y+92
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