Question

sum of the areas of two squares is 216 and the difference of their perimeter is 24 metre then find the side of the two square​

Answer 1

Step-by-step explanation:

let the side of two squares be x and y

x^2 + y^2 = 216

4x-4y = 24

x-y = 6

x = 6+y

(6+y)^2 + y^2 = 216

36 + y^2 + 12y + y^2 = 216

2y^2 + 12y - 180 = 0

y^2 + 6y - 90 = 0

after solving these equations you will get the values of x and y