Question

sum of the areas of two squares is 408 m^2. if the difference of their perimeter is 24 m , find the sides of the two squares​

Answer 1

Answer:

9+√195

3+√195

Step-by-step explanation:

let one square be a side of X

and other be y

so x²+y²=408. ----------(1)

and 4x-4y=24 I e x-y=6 ------(2)

now substitute 2 in one and a quadratic is formed

y²-6y-186=0

by finding it's roots we get

y=3+√195

now substitute this in eq 2

we get 9+√195