Math, asked by priyanshu8847, 5 months ago

sum of the areas of two squares is 468 m2. if the difference of their primeters os 24m. find the sides of the two squares.​

Answers

Answered by kapilchavhan223
3

Step-by-step explanation:

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Answered by sreemanthreddy673
0

Answer:

18 and 12

Step-by-step explanation:

a'2+b'2=468

4a-4b=24

so a-b=6

a=b+6

(b+6)'2+b'2=468

2b'2+12b+36=468

2b'2+12b=432

b'2+6b=216

b'2+6b-216=0

b'2+18b-12b-216=0

b(b+18)-12(b+18)=0

(b-12) (b+18)=0

so b=12 or -18

-18 is not possible

so b=12

so a=18

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