sum of the areas of two squares is 468 m2. if the difference of their primeters os 24m. find the sides of the two squares.
Answers
Step-by-step explanation:
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Answer:
18 and 12
Step-by-step explanation:
a'2+b'2=468
4a-4b=24
so a-b=6
a=b+6
(b+6)'2+b'2=468
2b'2+12b+36=468
2b'2+12b=432
b'2+6b=216
b'2+6b-216=0
b'2+18b-12b-216=0
b(b+18)-12(b+18)=0
(b-12) (b+18)=0
so b=12 or -18
-18 is not possible
so b=12
so a=18