Question

Sum of the areas of two squares is 468 metres square. if the difference of their perimeter is 24 metre find the sides of the two squares.

Answer 1

Question:

Sum of the areas of two squares is 468 metres square. if the difference of their perimeter is 24 metre find the sides of the two squares.

Answer:

Side of two squares= 12 m and 18 m.

Step-by-step explanation:

• Let the sides of two squares be x metre and y metre.
• The perimeter will be 4x and 4y
• The areas would be x square and y square.

ATQ,

It is given that,

4x-4y=24

x-y=6

x=y+6

Please refer to the attachment

However, side of square cannot be negative.

Hence, side of square are 12 m and 18 m.

$\huge \bold {{@QianNiu}}$