Question

Sum of the areas of two squares is 468m^2 if the difference of their perimeters is 24m find the sides of the two squares

Answer 1

Answer;

Perimeter of square =4a

4A-4a=24m

A-a=6m

A=6-a --------------------(1)

Area of square=a²

A²+a²=468

using (1)

(6-a)²+a²=468

a²+36-12a+a²=468

2a²-12a+36-468=0

2a²-12a-432=0

a²-6a-216=0