Math, asked by annu09, 1 year ago

sum of the areas of two squares is 468m sq .if. the difference between their perimeters is 24 m.find the sides of the two squares

Answers

Answered by leninviki
2
a^2+b^2=468
4a-4b=24
a-b = 6-------(1)
(a-b)^2=6^2
a^2+b^2-2ab=36
468-2ab=36
2ab=432
ab =216
(a+b)^2=a^2+b^2+2ab
(a+b)^2=468+432
(a+b)^2=900
a+b=30-------(2)

add(2)and(1)
2a=36
a=18
b=12
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