Question

Sum of the areas of two squares is 468m square. if the difference of their perimeter is 24 m,find the sides of two squares ​

Answer 1

Answer:

The sides of two squares are 12 m  and 18 m

Step-by-step explanation:

Let the sides of the squares be X,Y respectively

Given

sum of the areas  = 468 m²

X² + Y² = 468  ........(1)

difference of their perimeter = 24

4X - 4y  = 24

X - Y  = 6

 X  =  6 + Y   .......(2)

sub  (2) in (1)

(6+Y)²  + Y²  = 468

36 + 12Y +Y² +Y² = 468

2Y² +12Y - 432 = 0

Y² +6Y - 216 = 0

(Y- 12) (Y +18) = 0

Y = - 18 is admissable as it is -ve

∴ Y = 12

X = 6 + Y

   = 6 + 12

   = 18

Answer 2

Hope it helps u.....

plz mark it as BRAINLIEST....