sum of the areas of two squares is 468metre square.if the difference of their perimeter is 24m.formulae the quadratic equation to find the sides of the two squares
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let sides of two squares are x and y
then according to the ques.
x^2+y^2=468
and 4x-4y=24
on solving equation 2, we get, x=6+y
now put this, equation 1,
we get the quadratic equation in y.
this is the required equation.
on solving this equation we get
y=12, and x=18
then according to the ques.
x^2+y^2=468
and 4x-4y=24
on solving equation 2, we get, x=6+y
now put this, equation 1,
we get the quadratic equation in y.
this is the required equation.
on solving this equation we get
y=12, and x=18
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