sum of the areas of two squares is 468sq. cm if the difference of their perimeter is 24cm, find the sides of the two squares
Answers
Answered by
0
Answer:
If the difference of their perimeters is 24 m, find the sides of the two squares. According to question, (X)² + (Y)² = 468 m² ——(1). Side of second square = Y = 12 m.
Step-by-step explanation:
HOPE IT HELPS...
Similar questions