Question

Sum of the areas of two squares is 544 m² square if the difference of their perimeter is 32 m find the sides of the two square

Answer 1

Answer:

we can see that from above photo the

Answer is = 12 m and 20m

Answer 2

Answer:

Step-by-step explanation:sum of square is 544 cm2

Let the two square be a and b

Area =a2, b2

a2+b2=544cm2

Difference of perimeter= 32 cm

ie 4a-4b=32

4(a-b)=32

a-b=8

a=8+b

Substituting

a2+b2=544

(8+b)2+b2=544

64+16b+2b2=544

2b2+16b-480=0

÷2 b2+8b-240

-8+32/2, -8-32/2

12, -20

b=12

Substituting value of b

a=8+b

a=8+12

a=20

a=20 and b=12