Question

Sum of the areas of two squares is 544m². if the difference of their perimeter is 32m. find the sides of the two squares.

Answer 1

Answer:

Sum of the areas of squares=544m²

The difference between the area and the perimeter is 32m.

So the perimeter is

• 544-32=512m
• Sides of a square are equal.

Perimeter of square=4×side of square

So side of square = 512÷4=128m.

• The one side of one square is 128m.
• So the sides of squares is 128÷2=64m

Answer 2

Step-by-step explanation:

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