Question

Sum of the areas of two squares is 640 m2. if the difference of their perimeters is 64 m. find the sides of the two squares

Answer 1

Let side of first square be x and that of another be y

Ist case

area of square = (side)2

x2 + y2 =640 --------------------------   (i) 

2nd case

4x -4y =64

-> x-y=16

x=16+y

put value of x in 1

(16+y)2+y2=640

256+y2+32y+y2 =640

2y2 +32y =384

y2+16y=192

y2 + 24y-8y -192=0

y(y+24) -8(y+24)=0

y=8

and x=24

Answer 2

Your answer is in the attachment

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