Question

sum of the areas of two squares is 640m sq. If the difference of their perimeters is 64 cm.find the sides of the two squares

Answer 1

let a nd b be sides of 2 squares .

a^2+b^2=640

4a-4b=64

a-b=16

(a-b)^2=a^2+b^2-2ab

256=640-2ab

ab=192

b=192/a

a-b=16

a-192/a=16

a^2-16a-192=0

a=24 or -8(not possible)

if a is 24 then b is 8

Hence sides of 2 squares are 24 and 8