Question

sum of the areas of two squares is 850 m square . if the difference of their perimeter is 40 m. find the sides of the two square

Answer 1

Here is your answer mate..

Case 1 : let side of first square be s1 and its area be a1 and perimeter be p1

Case 2: let side of second square be s2 and its area be a2 and perimeter be p2

ATQ :-

a1 + a2 = 850 sq. m

s1^2 + s2^2 = 850 ---- 1.

p1 - p2 = 40 m

4×s1 - 4×s2 = 40 m

4 (s1 - s2) = 40 m

s1 - s2 = 10 m -----2.

s1 = 10 + s2

put the value of s1 in eq. 1

(10 + s2)^2 + s2^2 = 850

100 + s2^2 + 20×s2 + s2^2 = 850

2×s2^2 + 20×s2 = 850 - 100

2×s2^2 + 20×s2 = 750

2 (s2^2 + 10×s2) = 750

s2^2 + 10×s2 = 375

s2^2 + 10×s2 - 375 = 0

s2^2 + 25×s2 - 15×s2 - 375 = 0

s2 (s2 + 25) - 15(s2 + 25) = 0

(s2 - 15) (s2 + 25) = 0

s2 - 15 = 0. s2 + 25 = 0

s2 = 15. s2 = - 25

therefore : s2 = 15 m

now put the value of s2 in eq. 2

s1 = 10 + s2

s1 = 10 + 15

s1 = 25 m

Answer :-

s1 = 25 m

s2 = 15 m

hope this answer will help u...

thank u...

plz.. plz.. mark it as brainliest.

thank u..