Sum of the areas of two squares is 932 m2 . if the difference of their perimeters is 40 m,
find the sides of the two squares.
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Answer:
Side of square 1 is 26m ,
Side of square 2 is 16m.
Step-by-step explanation:
932 = (26)^2 + (16)^2
And 2( 26+26) = 104
2(16+16) = 64
Their difference is 40.
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THNX !
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