Question

sum of the areas of two squre is 468m qt the diffrent of their perimeter 24 m find the side of squre​

Answer 1

Answer:

If the difference of their perimeters is 24 m, find the sides of the two squares. According to question, (X)² + (Y)² = 468 m² ——(1). Side of second square = Y = 12 m.

Answer 2

Answer:

let side of larger square be x m

perimeter of larger square =4x m

perimeter of larger square -perimeter of smaller square=24m

4x-perimeter of smaller square =24

perimeter of smaller square 4x-24

4×side of smaller square =4x-24

side of smaller square =(x-6)m

ATQ

x²+(x-6)²=468

x²+x²-12x+36=468

2x²-12x-432=0

x²-6x-216=018-6

x²-18x+12x-216=0

x(x-18)+12(x-18)=0

(x-18)(x+12)=0

x-18=0,x+12=0

x=18,x= - 12

since side of a square can never be negative

so, side of larger square is =18m

side of smaller square is =18-6 =12 m.