Question

sum of the ares of two squares is 468msquare .if the difference of their perimeteris 24m,find the sides of the two squares.using quadratic equation.

Answer 1

Let sides be a and b

=>a^2-b^2 = 468

(a+b)(a-b) = 468

=>4a-4b = 24

a - b = 6

=> a+b = 78

=> 2a = 84

or a = 42

and b = 36