sum of the bases of the trapezium is equal to 36 cm and the distance between them is 12 cm. find the area
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Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD = 1/2 × a × h + 1/2 × b × h= 1/2 × h × (a + b) = 1/2 (sum of parallel sides) × (perpendicular distance between them)
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Answer:
216cm²
Step-by-step explanation:
Area of trapezium = sum of bases/2 * distance between parallel sides
= 36/2 * 12
= 36 * 6 = 216cm²
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