Question

sum of the cp's of two cars is Rs.150,000.ist car is sold at a profit of 20% and the second car at the loss of 20%.however,their S.p's are same. what is the cost price of the 1st car?; sum of the cp's of two cars is Rs.150,000.ist car is sold at a profit of 20% and the second car at the loss of 20%.however,their S.p's are same. what is the cost price of the 1st car?

Answer 1

solve further ... it is the method

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Answer 2

Answer:

Rs.60000

Step-by-step explanation:

Let the CP of first car be x

Since we are given that sum of the cp's of two cars is Rs.150,000.

So, CP of second car = (150000-x)

Now we are given that First car is sold at a profit of 20%

So, Profit on first car = 20% of x

                                 =$\frac{20}{100}x$

So, SP = CP +Profit

$Sp = x+\frac{20}{100}x$

Second car is sold at 20% loss

So, loss on second car = 20% of (150000-x)

$SP = (150000-x)-\frac{20}{100}(150000-x)$

Now we are given that their S.p's are same

So, $x+\frac{20}{100}x = (150000-x)-\frac{20}{100}(150000-x)$

$x+\frac{20}{100}x = (150000-x)-30000+\frac{20}{100}x$

$x = 120000-x$

$2x = 120000$

$x = \frac{120000}{2}$

$x = 60000$

Hence the cost price of first car is Rs.60000