Sum of the digit of a 2 digit number is 9 . When the digit are reversed ( interchanged ) . It is found that the resulting number is greater than the original number by 27 . Find the number .
Answers
Answered by
5
plzz
give
me
brainliest
ans
and
plzzzz
follow
me
please
Attachments:
Answered by
3
ANSWER:-
Given:
Sum of the digit of a 2 digit number is 9.
When the digit are reversed. It's found that the result number is greater than the original number by 27.
To find:
The number.
Solution:
Let the digit in ones place be R &
Let the digit in tens place be M.
⚫The original number is (10M+R)
⚫Reversed number is (10R+ M).
According to the question:
=) R+ M=9
=) R= 9-M.........(1)
Number obtained by interchanging the digits is greater than the original number by 27.
=) (10R+ M)= (10M+ R)27
=) 10R + M- 10M - R= 27
=) 9R - 9M= 27
=) R - M= 3
So,
=) 9- M - M= 3
=) 9 -2M= 3
=) -2M= 3-9
=) -2M= -6
=) M= -6/-2
=) M= 3
Therefore,
Putting the value of M in equation (1), we get;
=) R= 9 -3
=) R= 6
⚫The original number is 10M+ R
=) 10(3) + 6
=) 30 + 6
=) 36
Thus,
The number is 36.
Hope it helps ☺️
Similar questions