Question

sum of the digit of a two digit number is 11 when we interchange the digit it is found that the resulting new number is greater than the original number by 63 find the two digit number.

Answer 1

See the picture above there is the solution and answer is = 29
HOPE THIS WILL HELP AND PLZ MARK MY ANSWER AS BRAINLIEST....

Answer 2

let the number be 10x+y
on interchanging the digits the number will be 10y+x
a/q = x+y = 11
= y = 11-x - call this as equation 1
again a/q = 10y+x+63 = 10x+y
= 10y-y+x-10x+63 = 0
= 9y-9x+63 = 0
= 9(y-x+7) = 0
= y-x+7 = 0/9
= y-x+7 = 0 - call it as equation 2
put value of equation 1 in equation 2:-
= 11-x-x+7 = 0
= 11-2x+7 = 0
= 11+7 = 2x
= 18 = 2x
= 18/2 = x
= 9 = x
put x = 9 in equation 1 ,we get :-
= y = 11-x
= 11-9
= 2
the two digit number will be :-
= 10x+y (put values of x and y)
= 10*9+2
= 90+2
= 92
Verification :- the sum of the two digits is 11
= 9+2=11
on interchanging the digit it is found that the resulting new number is greater than the original number by 63
= 92-29
= 63

HOPE IT HELPS