Question

Sum of the digit of a two digit number is 12 if the digits are reversed the new number formed is 36 less than the original number find the original number

Answer 1

Answer:

Step-by-step explanation:

LET THE NO. BE 10A+B.

A+B=12. EQ-1

AFTER REVERSING THE DIGITS,

10B+A=10A+B- 36

9B-9A=-36

9(B-A)=-36

A-B=4. EQ-2

FROM EQ 1 AND 2, WE GET,

A=8 AND B=4.

SO, THE ORIGINAL NO.= 10A+B

=10*8+4=84