sum of the digit of a two digit number is 6 the number obtained by interchanging the digit exceed the given number by 18. find the given number
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Let Ten’s digit=x
Therefore, One’s digit=6−x
No.=10(x)+1(6−x)
=10x+6−x
=9x+6
Interchanged no=10(6−x)+x
=−10x+60+x
=60–9x
From the question::
9x+6+18=60–9x
18x=36
x=2
The no. is=24
Therefore, One’s digit=6−x
No.=10(x)+1(6−x)
=10x+6−x
=9x+6
Interchanged no=10(6−x)+x
=−10x+60+x
=60–9x
From the question::
9x+6+18=60–9x
18x=36
x=2
The no. is=24
ayush914:
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