sum of the digit of a two digit number is 7 when we interchange the digit it is found that the resulting new number is greater than the original number by 27 what is the two digit number
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Okay so let the 2 number be x and y,
Then x+y=7
The original number will be (10x+y) as y is in unit's place and x is in ten's place after reversing we will get (10y+x)
so (10x+y) - (10y+x)=27
Solving it, 10x-x-10y-y=27
9x-9y=27
9(x-y)=27
x-y=3 (dividing by 9 on both side)
So we get 2 equations
x+y=7 and x-y=3
By solving them,
x + y = 7
- x + y = -3
We get 2y=4, so y =2
Putting the value of y in any equation we get x=5.
Hope this helps
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