sum of the digit of a two digit number is 9. if the number obtained by reversing the order of digit is 27 more than the original number, find the original number.
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Answer:
36
Step-by-step explanation:
(90-9x)=(9x+9)+27
90-9x=9x+36
-9x-9x=36-90
-18x=54
x=-54/-18=3
(9×3+9)=27+9=36
=36
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