Sum of the digit of a two digit number is 9 when we interchange the digit it is found that the resulting new number is greater than the orginal number by 27 what is the 2 digit number
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Let the unit digit be y and tens digit be x Number formed = 10x + y Reverse number = 10y + x x + y = 9 (Given)…………………………eq1 10y + x = 10x + y + 27…………………….eq2 9y - 9x = 27 y - x = 3……………………………………..eq3 Solving eq1 and eq3 ,we get x = 3 and y = 6 Original Number = 36 Reversed Number = 63
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