Sum of the digit of a two-digit number is 9.when we interchange the digits,it is found that the resulting new number is greqter than the original number by 27. What is the two digit number
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Answered by
0
X + Y = 9
X = 9 - Y - eq. 1
Given :
(10Y + X) - (10X + Y) = 27
10Y + X - 10X - Y = 27
9Y - 9X = 27
Divide the entire equation by 9
Y - X = 3
From eq. 1 we know, X = 9 - Y
Thus,
Y - (9 - Y) = 3
Y - 9 + Y = 3
2Y = 3+ 9
2Y = 12
Y = 12/2 = 6
From eq. 1,
X = 9 - Y
X = 9 - 6
X = 3
Therefore,
The no. is 10X + Y
= 36
Hope it helps :)
X = 9 - Y - eq. 1
Given :
(10Y + X) - (10X + Y) = 27
10Y + X - 10X - Y = 27
9Y - 9X = 27
Divide the entire equation by 9
Y - X = 3
From eq. 1 we know, X = 9 - Y
Thus,
Y - (9 - Y) = 3
Y - 9 + Y = 3
2Y = 3+ 9
2Y = 12
Y = 12/2 = 6
From eq. 1,
X = 9 - Y
X = 9 - 6
X = 3
Therefore,
The no. is 10X + Y
= 36
Hope it helps :)
Answered by
0
Hey friend,
Here is the answer you are searching for,
Let the digits be x,y
Given,
x+y = 9
=> y = 9-x
Let the original number be (10y + x),
New number be (10x + y),
Also given,
(10y + x) + 27 = (10x + y)
By taking y as (9-x),
=> 10(9-x)+x+27 = 10x+9-x
=> 90-10x+x+27 = 9x+9
=> 117-9x = 9x+9
=> 18x = 108
=> x = 108/18 = 6
=> y = 9-6 = 3
Therefore,
Digits = 3,6
=> Original number = 36
HOPE IT HELPS YOU.
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