Question

sum of the digit of a two digits is 9.when we interchange the digits it is found that the new number is greater than the original number by 27 what is the two digit number​

Answer 1

Answer:

Step-by-step explanation:

Let the digit at ones place be x and tens place be 9-x

10(9-x)+x

90-10x+x

90-9x

After interchanging

Ones place=9-x ,tens place=x

10(x)+9-x

10x+9-x

9x+9

New no. Is greater then original no.

(9x+9)-(90-9x)=27

9x+9-90+9x=27

18x-81=27

x=6

Original no.

Ones place=x=6

Tens place =9-x=9-6=3

Therefore original no. Is 63