Math, asked by OMBorawar, 11 months ago

sum of the digit of two digit no. is 15. The no. is deceased by 27 of the no. is reversed. find the no.​

Answers

Answered by vamshimadineni123
1

Answer:

96

Step-by-step explanation:

let two digits be x,y

given x+y =15                          (a)

xy can be written as x*10+y                       (1)

if xy is reversed it will 10*y + x                 (2)

given (1) -(2) = 27

so 9x-9y =27

===>x-y=3                              (b)

solving a and b

we get x =9,y=6


OMBorawar: how 9 and 6 came
vamshimadineni123: equation a is x +y =15, equation b is x-y =3 adding both we get 2x=18 ==> x=9
vamshimadineni123: substitute x =9 in equation a ==>9+y = 15==>y=6
vamshimadineni123: hope you understood
OMBorawar: Ok thank you i understoor
OMBorawar: understood
vamshimadineni123: give me brainy answer
OMBorawar: sir again one question
Answered by TheCommando
14

Question:

The sum of the digits of two digit number is 15. The number is decreased by 27, if the number is reversed. Find the number.

Solution:

Let the digit at unit place = x

Let the digit at tens place = y

Given:

x + y = 15 (Equation 1)

The number is 10y + x

The reversed number is 10x + y

According to question

10y + x - 27 = 10x + y

10y + x - 10x - y = 27

9y - 9x = 27

y - x = 3 (Equation 2)

Adding Equation 1 and Equation 2

x + y + y - x = 15 + 3

2y = 18

y = 9

Putting value in Equation 1

x + y = 15

x + 9 = 15

x = 15 - 9

x = 6

Therefore, the number is 96.

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