Question

Sum of the digits of a 2 digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54, then the original number is

Answer 1

Answer:

Let, Digit at ones place= x

Digit at tens place =12-x

Original Number = 10(12-x)+1(x)

=120-10x+x

=120-9x

New number =10(x)+1(12-x)

=10x +12-x

=9x +12

A/c to Question

9x +12=120-9x +54

»9x+9x = 120+54+12

» 18x = 186

» x= 186/18

»x =10.33

Hence, Digit at ones place = 10.33

Digit at tens place = 12-10.33

= 1.67

Rounding te digits the number = 210