Question

sum of the digits of a 2-digit number is 6. If the digits of the numbers are reversed, the new no. is decreased by 36. Find the number.​

Answer 1

Let the number be 10x+y
If x+y =6
According to the question,
(10x+y)-36 =10y+x then
=>(10x+y)-(10y+x) =36
=>9x-9y =36
=>9(x-y) =36
=>x-y =36/9
=>x-y =4
(x+y)+(x-y)=6+4
=>2x =10
=>x =5
Then y =6-5
=1
Therefore the number is 51

Answer 2

Answer:

Let the number be 10x+y

If x+y =6

According to the question,

(10x+y)-36 =10y+x then

=>(10x+y)-(10y+x) =36

=>9x-9y =36

=>9(x-y) =36

=>x-y =36/9

=>x-y =4

(x+y)+(x-y)=6+4

=>2x =10

=>x =5

Then y =6-5  

=1

Therefore the number is 51

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