Question

sum of the digits of a 2-digits number is8.the given number exceeds the number obtained by the interchanging the digit by 8.find the given number.
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Answer 1

solution

let the unit digit be x

and ten digit be y

so number formed =10y+x

a/q

x+y=8............(1)

10y+x=10x+y+18

9y-9x=18

y-x=2.........(2)adding equations (1) and (2)then we get

2y=10y=5

put the value of y in equation (1)

then we get x=3

so required number is 10×5+3=53 Ans