Question

sum of the digits of a 2digit no is 10 l. the no obtained by interchanging the digits exceeds the original no. by 36 . find the original no.​

Answer 1

$10x+y$ - the original number

$x+y=10\\10y+x=10x+y+36\\\\x+y=10\\9x-9y=-36\\\\x+y=10\\\underline{x-y=-4}\\2x=6\\x=3\\\\3+y=10\\y=7\\\\10\cdot 3+7=37$

37

Answer 2

Step-by-step explanation:

let one digit be x and other be y.

Now the sum=10x+10y

10x+10y = 10. (1)

Now. Interchanged digit

10y+10x=36. (2)

Now subtracting both 1&2

We get ,x+y=1. Y+x=26