Sum of the digits of a number is 9.When we interchange the digits, it is found that the resulting new number is greater than the original number by 27.What are the two-digit numbers?
Answers
Answer:
Step-by-step explanation:
The sum of the two digits is 9.
On interchanging the digits, the resulting new number is greater than the original number by 27.
Let us assume the digit of units place be x.
Then the digit of tens place will be 9-x.
Thus the two-digit number is 10(9-x) + x
Let us reverse the digit
the number becomes 10x + (9-x).
As per the given condition
10x + (9-x) = 10(9-x) + x + 27
= 9x + 9 = 90 – 10x + x + 27
= 9x + 9 = 117 – 9x
On rearranging the terms we get,
=18x = 108
x = 6
So the digit in units place is 6
Digit in tens place is 9-x= 9-6=3
number is 36
On interchanging the digits, the resulting new number is greater than the original number by 27. Let us assume the digit of units place be x. Then the digit of tens place will be 9-x. the number becomes 10x + (9-x).
Hoe this helps you.
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