Question

Sum of the digits of a number is 9.when we interchange the digits, it is found that the resulting new number is greater than the original number by 27.what is the two-digit number.?

Answer 1

Answer:

Let the number at tens place be x.

So number at ones place will be 9-x.

Original number = 10x - 9-x

                            = 9x - 9

New number = 10(9-x) + x

                      = 90 - 10x + x

                      = 90 - 9x

ATQ - 9x - 9 + 27 = 90 - 9x

                9x + 18 = 90 - 9x

               9x + 9x = 90 - 18

                      18x = 72

                          x = $\frac{72}{18}$

                          x = 4

Original number = 9 × 4 - 9 = 27