sum of the digits of a two digit no. is 5 . when the digits are reversed , the resulting no. is greater than the original no. by 27. find the no.
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Answer:
THE NUMBER IS 14
Step-by-step explanation:
LET THE NUMBER BE xy
SO,
A.T.Q.,
x+y=5
x=5-y
NOW,
A.T.Q.,
yx = xy+27
10y+x=10x+y+27
10y+(5-y)=10(5-y)+y+27
9y+5=50-10y+y+27
9y+5=77-9y
9y+9y=77-5
18y=72
y=72/18
y=4
SO,
x=5-y
x=5-4
x=1
SO,
THE NUMBER WAS xy WHICH IS 14
I HOPE YOU UNDERSTOOD THE QUESTION!!!
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