Sum of the digits of a two digit number is 10. When we interchange the digits, it is found that the resulting number is greater than the original number by 36. Find the number.
Answers
Let the two digits of the number be:
- x and y
Let the number be:
- 10x+y
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It's given that
- Sum of two digits = 10
Thus,
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Also given,
when we interchange the digits, the resulting number is greater than the original number by 36.
The original number = 10x+ y
The number after interchanging the digits= 10y+ x
10y+ x = 10x+ y + 36
→ 10y- y + x -10x =36
→ 9y -9x = 36
→ 9(y-x)= 36
→
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Adding i and ii we get,
x+y + y -x = 10+ 4
→ 2y = 14
→ y =7
Substitute y=7 in equation ii,
y- x=4
→7- x =4
→ x = 7-4
→ x =3
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Thus the number is:
10x + y
→ 10×3 + 7
→
∴ The number is 37
Given
- Sum of the digits of a two digit number is 10.
- When we interchange the digits, it is found that the resulting number is greater than the original number by 36.
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To find
- The required number.
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Solution
- Let the tenth digit number be x.
- Let the ones digit number be y.
Therefore,
- Required Number = 10x + y
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★ It is given in the question that sum of the two digits is 10.
⠀⠀....[1]
⠀
★ When we interchange the digits, it is found that the resulting number is greater than the original number by 36.
⠀
- After interchanging = 10y + x
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According to the question
⠀
⠀
⠀
⠀
⠀
⠀⠀.....[2]
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★ Adding equation [1] and [2]
⠀
⠀
⠀
⠀
⠀
★ Putting the value of y in equation [1]
⠀
⠀
⠀
Hence, the required number is
⠀
Therefore,
- Required Number = 37
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