Question

sum of the digits of a two digit number is 11 the given number is less than the number obtained by interchanging the digits by 9 find the number​

Answer 1

Answer:

56

Let tens digit be x and ones digit be (11-x)

ATQ

10x+(11-x)+9=10(11-x)+x

10x+11-x+9=110-10x+x

9x+20=110-9x

9x+9x=110-20

18x=90

X=90/18=5

Therefore, the number

=10x+(11-x)

=10×5+(11-5)

=50+6

=56

Step-by-step explanation:

Hope it helps....