Question

Sum of the digits of a two-digit number is 11. the given number isless than the number obtained by interchanging the digits by 9.find the number.

Answer 1

where two numbers are x,y
here sum of digits is 11=x+y=11....(I)
two digit number is=10x+y
the numeber is less than 9 that time the digits interchange between them=10x+y-9=10y+x
10x-x+y-10y=9
9x-9y=9
x-y=1..(ii)
x=1+y
put x value in equ (I)
x+y=11
1+y+y=11
2y=10
y=5
put y value in equ (I)
x+y=11
x=11-y
x=11-5
x=6
ans:two digit number=10x+y=10*6+5=65

Answer 2

i hope this will help you