Question

sum of the digits of a two-digit number is 11, when we interchange the digits, it is found that the resulting new number is greater than the original number by 63. Find the two digit number?

Answer 1

Sum of two digit no. is 11.
= a+b=11
Original no.=10a+b
No. formed by interchanging its digit =10b+a
Now, its given that-
(10b+a)-(10a+b)=63
10b+a-10a-b=63
9b-9a=63
9(b-a)=63
b-a=7
Now ,by subtraction = b-a=7 from a+b= 11
We get= 2b=4
b=4÷2=2
So, b =2
Then,
a+b=11
a+2=11
a=11-2
a=9
Hence, the original number=92.(Answer)