Math, asked by beg123, 1 year ago

Sum of the digits of a two digit number is 11. When we interchange the digits it is found that the resulting new number is greater than the original number by 63. find the two digit number

Answers

Answered by dpsdurgstudent

Let the tens and unit digits be x & y respectively.

Therefore,
x + y = 11 (1)

Original number:- 10x + y
Number formed on reversing the digits:- 10y+ x

ATQ,
$10x + y = 10y + x + 63 \\ 9x - 9y = 63 \\ x - y = 7 \: \: \: \: (2)$

(1) + (2)
x = 9
Substituting this in (2) we get
9 - y = 7
y = 2

Hence two digit number = 10x + y
= 10(9) + 2
= 92

beg123: how came original number = 10x + y

dpsdurgstudent: Tens digit is 10 × x

beg123: what is (1) and (2)

dpsdurgstudent: equation 1 & equation 2

beg123: give the equation for (1) + (2)

dpsdurgstudent: y is eliminated and x x becomes 2x

beg123: how

beg123: write in full form (1)+(2)

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