Math, asked by Choteylal, 9 days ago

Sum of the digits of a two-digit number is 12. The given number exceeds the number obtained by reversing the digits by 36. Find the given number.​

Answers

Answered by dishti9b
0

Step-by-step explanation:

Correct answer

9and 3

9+3=12

Answered by sandeeprkpsk
1

Step-by-step explanation:

Let the two digit number be of the form =10X+Y

Sum of the digits =X+Y=12

Reverse number =10Y+X

Given number=Reverse number +36

10X+Y=10Y+X+36

10X+Y-10Y-X=36

9X-9Y=36

9(X-Y)=36

X-Y=4

Substitute in X+Y=12

Y+4+Y=12

2Y=8

Y=4

X=Y+4

X=4+4=8

Given number=10X+Y=10(8)+4

=80+4

=84

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